What's the magical floor for a bullet such as those made with ww's(BHN 12) to obturate? Would it need at least about 16,000 psi for instance? It seems I've seen a formula for this but can't recall where. The reason I ask is that I just acquired a 38 Special(Model 15-3) and was going to load some with 6 gr of HS-6 with the 158 gr boolit and according to Hodgdon's website that yields about 16,000 cup which I can't relate to in psi but assume it's around 12,000 or less psi. I may have to go to a softer boolit such as with isotope lead around BHN 10.
Am I way off in my thinking or close to the specifics desired? Another load I want to test is 4 gr of Universal for about the same pressure as the load with HS-6 and velocity about equal. In short, do I need a softer boolit than ww's?